How to display all of the ascii characters

[Jeff Ciaccio]

I am trying to write a little code to display all of the ascii characters, but it doesn't seem to like to concatenate the backslash with an int. Any ideas on how to get this to work?

Thanks!!

private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) {
   String esc;
   
   for (int i = 1; i < 400; i++)
   {
      esc =  "\"+i;
      System.out.println(i + ": " + esc);// TODO add your handling code here:" +
   }
}

[Campbell Ritchie]

The escape characters for \123 are in octal. Try 0400 instead of 400. Some of them are control characters, which don't print. Two are line end characters, so you only see a line break.
And it's "\\" not "\".
Make sure to print \007 several times

[Jeff Ciaccio]

When I make it "\\", I only get the following:
1: \1
2: \2
3: \3
4: \4
5: \5
6: \6
7: \7

But I want to see the characters for each. I don't want to have to put in "\1" "\2" etc so I am trying to get a loop to do this for me.

[Rob Spoor]

How about simply casting it to char?

char esc;   
for (int i = 1; i < 400; i++)   
{   
    esc = (char)i;
    System.out.println(i + ": " + esc);// TODO add your handling code here:" +   
} 

Also, ASCII ends at 127. Everything beyond that is no longer ASCII.