Evaluation problem

[Rajesh k Jha]

Can somebody make me understand how the value of j is evaluating in the commented line

class incdec
{
public static void main(String[] args)
{
int j=5;
int k;
k=j++ + --j;// How it is evaluation
k++;
System.out.println("k="+k);
}
}

[Vijitha Kumara]

With the post increment operator when used in an expression value will be incremented/decremented by one but the previous value is used.
So the line,

 k=j++ + --j   

can be interpreted as,

k = 5 + 5 //(for the --j initial value is 6 which was incremented earlier by j++)

[Garlapati Ravi]

remember this:
post-increment -> participates in expression and then increment
pre-increment -> increment and participate in expression

int j=5;
int k;
k=j++;
System.out.println("k="+k); // prints 5
(or)
int j=5;
int k;
k=++j;
System.out.println("k="+k); // prints 6


j++ + --j;
5 + (6-1)5 = 10

[Lucas Smith]

class incdec
{
    public static void main(String[] args)
    {
        int j=5;
        int k; 
        k=j++ + --j;// j++
                  
        k++;
        System.out.println("k="+k);
}
}

It's pretty siple - the output is 11.
[value 5 is taken(it's post incrementing so we take j value in this expression and j+1 in the next expression with j) + --j(value 5 is taken - it's predecrementing but j has value of 6 because it was postincremented)]

[Rajesh k Jha]

Hi Ravi,
Your example really clarified all my steps of postincrement and preincrement.
Thanks a lot..

[Ankit Garg]

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