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error in servlet compile

satyasandha samal

Joined: Aug 11, 2009
Posts: 5
i have face a problem for runnimg servlet
java_home=C:\Program Files\Java\jdk1.5.0_15;

i have set path =C:\Program Files\Java\jdk1.5.0_15\bin;C:\Program Files\apache-tomcat-5.5.28;
set classpath=C:\Program Files\apache-tomcat-5.5.28\lib\servlet-api.jar; C:\Program Files\apache-tomcat-5.5.28\lib\jsp-ap.jar;
when i am compile under C:\Program Files\apache-tomcat-5.5.28\webapps\jsppage\classes
getting error
as package javax.servlet does not exist
please help what i am wrong

Jesper de Jong
Java Cowboy
Saloon Keeper

Joined: Aug 16, 2005
Posts: 15092

Welcome to JavaRanch.

How exactly are you compiling your source code, are you doing that on the command line, or are you using an IDE?

When you set the classpath, you have to be careful with spaces in the path. Try this:

set classpath="C:\Program Files\apache-tomcat-5.5.28\lib\servlet-api.jar";"C:\Program Files\apache-tomcat-5.5.28\lib\jsp-api.jar";.

Note: Paths with spaces in them are in "quotes", and there must not be a space between the ; and the next entry in the path.

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Campbell Ritchie

Joined: Oct 13, 2005
Posts: 46373
Please look at our Servlets FAQ, and also check whether you need to download anything more than the standard Jave installation.

Moving to servlets forum.
I agree. Here's the link:
subject: error in servlet compile
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