Resume of program

[sandeepkumar patil]

hi

Following is scenario

1 public amethod()
2 {
3 int j=45/0;// Here code will throw runtime exception
4 system.out.println("Hi");
5 }

I want to execute code of line 4 any way .

please help me how we can resume program after throwing an exception on line 3 .

Thanks

[Rob Spoor]

Catch the exception.

[sandeepkumar patil]

I can code like this
try{
public amethod()
{
int j=45/0;// Here code will throw runtime exception
system.out.println("Hi");
}
} catch(Exception ex)
{
}

but I cant put try- catch like this

public amethod()
{
try{

int j=45/0;// Here code will throw runtime exception
catch(Exception ex)
{
}

system.out.println("Hi");
}
}

[Sebastian Janisch]

Please put your code between the code tags.

Your code throws a ArithmeticException which is of type RuntimeException and hence unchecked.

so, you need to catch either of the two.

[Joanne Neal]

finally can be used even if you aren't catching an exception

try{ 
    int j=45/0;// Here code will throw runtime exception 
} finally { 
    system.out.println("Hi"); 
} 

[Sebastian Janisch]

Joanne Neal wrote:finally can be used even if you aren't catching an exception

try{ 
    int j=45/0;// Here code will throw runtime exception 
} finally { 
    system.out.println("Hi"); 
} 

Which is a better approach since the sysout is not an exception handling and should be executed whether or not an exception occurs.