which draw() is called?

[Ankur kothari]

     class Shape{ 
	   int rad=6;
	   {
		   System.out.println(rad);
	   }
      void draw(){System.out.println("Ankur");}      
     
       Shape() {    //shape constructor  
       System.out.println("Shape() before draw()"+rad);  
       draw();                                                             
        System.out.println("Shape() after draw()"+rad);  
      }  
    }  
     
   class RoundShape extends Shape {  
     private int radius = 1; 
	   {
		   System.out.println(radius);
	   }
     
     RoundShape(int r) {  
       radius = r;  
       System.out.println("RoundShape.RoundShape(), radius = " + radius+ " "+rad);  
     }  
     {System.out.println("Ankur1");}
     void draw() {  
       System.out.println("RoundShape.draw(), radius = " + radius+ " "+rad);  
     }  
   }  
     
   public class ContructPoly {  
     public static void main(String[] args) {  
       new RoundShape(5);  
     }  
   }    

when the super class constructor is executed which draw method is called? I was expecting superclass's draw() to be called but that wasn't the case

[Ankit Garg]

I was expecting superclass's draw() to be called

Why would draw() in Shape class be called. The draw method in RoundShape class overrides the draw method of shape class so the call will be polymorphic...

[Ankur kothari]

but draw() is being called from within the Shape constructor....

[Ankur kothari]

Ankit is it because at run time the jvm decides which draw method to call based on the object?

[Ankit Garg]

ankur kothari wrote:Ankit is it because at run time the jvm decides which draw method to call based on the object?

Bang on target, that's right, the call will be decided based on the actual object

[Ankur kothari]

Thanks a lot