how to copy a file to a different location with a part of the file name as the filename

[rahulJ james]

I have set of files residing in my hone directory in different naming conventions as shown below,

ap_aearo_prod.20091104044210.Z.20091106.212217
ap_boise_prod.20091029064716_sorted.Z.20091106.212201
ap_boise_prod.20091029064716.Z.20091106.212158
arms_820i_prod.000003ywS.Z.20091109.064508

I wanted to copy these files to a different location with the filename being only till the "Z" i.e.; this file ap_aearo_prod.20091104044210.Z.20091106.212217 has to be copied as ap_aearo_prod.20091104044210.Z, have to truncate the part after the Z.

I have set of files under this directory. This set of files can be identified by the combination of ap_*_prod*20091106* as I need only these files from this datestamp, I have unwanted files with the same datestamp as well.

Can anyone advise

[Himanshu Rawat]

I tried below code on your mentioned files. Give it a try.

   #!/usr/bin/perl

@files = <*>;
foreach $file (@files) {
  print "File name = $file \n";
  $locationZ = index($file,"Z");
  print "location of Z = $locationZ \n";

  $newFileName = substr($file,0,$locationZ + 1);
  print "New File name = $newFileName \n";

  system("cp $file $newFileName");
}

 

PS : Script was in same directory where files are. Customise it

[rahulJ james]

Sorry I forgot to mention that I need the script in UNIX. I am sorry for that

[Himanshu Rawat]

It's perl script and ran it on linux/unix

[rahulJ james]

when you say in your code as <*>, I beleive it will pick all the files under that directory but I want only the files matching as I have explained above

[Himanshu Rawat]

  # @files = <*>;     

this to

# @files = <ap_*>;  

This will take only those files starting with ap_

Hope this helps now

[Stefan Wagner]

create a local script

# adhoc.sh:
FILE=$1
mv $1  /new/target/${FILE/Z*/Z}

chmod a+x adhoc.sh, and

find . -name "ap_*_prod*20091106*" -exec ./adhoc.sh {} \;

[rahulJ james]

It worked. Thanks