Maybe I miss something

[Avi Freege]

This is my code:

while (LegalSlot == 0) {
if (gslots[anser].getplaya() > 0) {
gslots[anser].removplayer(1);
if (gslots[anser+numcube].getladderRope() == 0) {
gslots[anser+numcube].addplayer(1);
} else {
gslots[gslots[anser+numcube].getladderRope()].addplayer(1);

}
flag++;
LegalSlot = 1;
} else {
System.out.println("Ilegal Slot Pick Again;");
try {
anser = (input.nextInt())-1;
} catch (InputMismatchException e) {

}
}
Now I want to catch the exception if the user enters char such has 'a' 'b' and anything other than int , but when he catches the exception I want him to come back to the line : anser = (input.nextInt())-1;
to recieve new input from the user but somehow he just keep going threw the code. So my question is how do I make him come back to the the input line I mentioned?
thanks.

[Ireneusz Kordal]

System.out.println("Ilegal Slot Pick Again;"); 
boolean ok = false;
boolean abort = false;
while ( ! ok )
try { 
  anser = (input.nextInt())-1; 
  ok = true;
} catch (InputMismatchException e) { 
  System.out.println("Incorrect number. Enter 'a' to abort or press Enter to try again!"); 
  String s = input.next();
  if(  s.compareToIgnoreCase('A') == 0 ){
     ok = true;
     abort = true;
  }
 }
if( abort ){
 // ... user entered 'abort'
}     

[Avi Freege]

I tried that for some reason he is going back to the start of the loop and completely ignores the raw:

try {
anser = (input.nextInt()) - 1;
} catch (InputMismatchException e) {
System.out.println("Please Try Again");

thats gets an input from the user and I get the loop keep going and going
I debuged it and I dont understand why when he reaches the raw
anser = (input.nextInt()) - 1;
he is not stopping and waiting for an input
hope someone can explain it to me.
but thanks.

[Campbell Ritchie]

Welcome to JavaRanch

Rob Prime points out it is completely possible to avoid the InputMismatchException like this, or something rather similar:

private Scanner input;
 . . .
int i;
 . . .
while (!input.hasNextInt())
{
   input.next();
   System.err.println("Incorrect entry: not a number");
}
i = input.nextInt();

[Jesper de Jong]

Avi, welcome to JavaRanch.

Please use code tags when you post source code, so the forum can format it for you.

[Rob Spoor]

Campbell Ritchie wrote:Welcome to JavaRanch

Rob Prime points out it is completely possible to avoid the InputMismatchException like this, or something rather similar:

private Scanner input;
 . . .
int i;
 . . .
while (!input.hasNextInt())
{
   input.next();
   System.err.println("Incorrect entry: not a number");
}
i = input.nextInt();

Correct. The input.next() inside the method is used to consume the non-int. The guard is slightly wrong though; it should also check for input.hasNext:

while (input.hasNext() && !input.hasNextInt()) // there is something, just not an int
{
    input.next();
    System.err.println("Incorrect entry: not a number");
}
if (input.hasNext())
{
    // the stream hasn't closed yet so there is an int
}// else the stream has closed; close the app?

I think I forgot the hasNext() before in the loop, but that could cause an exception with the input.next() call if the stream is closed.