How come the instantiation of interface workes in my code

[Rahul Shivsharan]

 interface Ex01_24_09 {
		
		void myMethodOne();
		void myMethodTwo();
} 

public class Ex02_24_NOV_09 {
	public static void main (String [] args){
		Ex01_24_09 ex01 = new  Ex01_24_09(){
			
			@Override
			public void myMethodOne(){
				System.out.println(" :- myMethodOne ");
			}
			
			@Override
			public void myMethodTwo(){
				System.out.println(" :- myMethodTwo ");
			}
		};

		ex01.myMethodOne();	
		ex01.myMethodTwo();	
	}
}   

can anybody tell me wether we have instantiated interface or what ? i'm not able to understand the above code and how it works

[Ulrika Tingle]

Rahul Shivsharan wrote:
can anybody tell me wether we have instantiated interface or what ? i'm not able to understand the above code and how it works

You've instantiated an anonymous class.

Anonymous means the class has no name.

The anonymous class is defined on the fly in code, so you can do new on it.

[Manu Ullas]

Rahul Shivsharan wrote:
can anybody tell me wether we have instantiated interface or what ? i'm not able to understand the above code and how it works

Ulrika Tingle is right. Ex01_24_09 is an anonymous-inner class that implements the Ex01_24_09 interface implicitly. It is anonymous because it doesn't have any name that you can use to refer to it later. And inner because it is defined as part of a statement in a method.

Also ex01 is an object of the anonymous class Ex01_24_09.

This should be able to explain anonymous and inner classes in detail.