why does core java doesnt have unsigned int??

[Vishal Hegde]

why does core java doesnt have unsigned int???


and why whenever an unsigned varible assigned a negative number in C++,doesnt create an errorr?

[Ryan Webb]

no unsigned for primitives kinda suck huh?

in my opinion, this is for portability purposes...
unsigned types tend to have larger values than signed types
creators of java want to make sure whether on any platform you use java values have the same limit on primitives

More Info here

[Vishal Hegde]

i know this is a java forum but please do answer this qustion on c program


unsigned int a=-5;


when i tried to compile and run it it displayed -5


usigned int states that it has only positive value???
now what is going on here ???

[Campbell Ritchie]

You are obviously taking the bits of the signed number -5, which in 32 bits is 2^32 - 5. Since C isn't a type-safe language, it will take the same bit pattern as that and covert it to positive or negative numbers depending on whether you use the %u or %i flags to display it.

#include <stdio.h>
#include <stdlib.h>

void printSigned(int*);
void printUnsigned(int*);
void readInt(int*);

int main()
{
    int i = 0;
    do
    {
        printSigned(&i);
        printUnsigned(&i);
        readInt(&i);
    } while (i); /* C-style cheat using 0 for false and non-zero for true */
    return 0;
}//end main

void printUnsigned(int* iPt)
{
    printf("Unsigned value of i = %u\n", *iPt);
}//end print unsigned

void printSigned(int* iPt)
{
    printf("Signed value of i   = %i\n", *iPt);
}//end printSigned(int*);

void readInt(int *iPtr)
{
    printf("Please enter int number, or 0 to finish repetition: ");
    scanf("%i", iPtr);
}//end read int

Try that, remembering the scanf . . . %i will take 2147483647 (maximum value of int) for anything larger.