enum methods

[Jack Bento]

Hi

Please help me understand the difference between these 2 methods. How would I call them? Why is the first one enclosed in curlys?

Thanks!

enum SG{
	POSH, BABY, SPORTY, SCARY 
	{
		public String spice1(){
			return "one";
		}
	};
	public String spice2(){ 
		return "two";
	}
}

public class Pop{
	public static void main (String [] args){
		System.out.println(new SG.spice());
	}
}

[Minhaj Mehmood]

are you able to compile this code?

[Costi Ciudatu]

First, let me try to make your code compilable (and a little more relevant):

enum SG{
	POSH, BABY, SPORTY, SCARY 
	{
		public String spice(){
			return "one";
		}
	};
	public String spice(){ 
		return "two";
	}
}

public class Pop{
	public static void main (String [] args){
		System.out.println(SG.BABY.spice());		// prints "two"
		System.out.println(SG.SCARY.spice());	// prints "one"
	}
}

SCARY overrides the spice() method, that's why it is declared inline (in curlys).
'new' is not suitable for enums in general (not to mention that

new SG.spice()

is syntactically wrong.

[Minhaj Mehmood]

enum SG{
	POSH, BABY, SPORTY, SCARY
	{
		public String spice2(){
			return "one";
		}
	};
	public String spice2(){
		return "two";
	}
}

public class Pop{
	public static void main (String [] args){
		System.out.println(SG.SCARY.spice2());
	}
}

the above code you can compile and run successfully.

[Jack Bento]

System.out.println(SG.SCARY.spice1());

does not compile?

[Jack Bento]

Sorry I get it now. The first method belongs to scary. Thanks for helping me.

[Minhaj Mehmood]

Jack Bento wrote:

System.out.println(SG.SCARY.spice1());

does not compile?

dint get you??