Exceptions

[Neil Muya]

Hi,

Just want to clarify something with Exception:

 
class Animal{
	public void eat() throws Exception{
		System.out.println("Animal");
	}
}
public class Frog extends Animal{
	public void eat(){
		System.out.println("frog");
	}
	public static void main(String args[]){
		Animal a = new Frog();
		Frog f = new Frog();
		a.eat();
		f.eat();
	  }
	}

In this code a.eat() calls the eat method of Frog not Animal.

Then why does a.eat() gives a compile error that it should Handle/Declare?

Maybe there is a rule I'm missing . Hope you could help me.


Thanks in Advance!

[Simran Dass]

Compiler checks the reference type of the variable. In case of overriding which method
will be called is decided at runtime. In the line :

Animal a = new Frog();

Compiler sees that a is of type Animal . But the eat() method in class Animal throws Exception
which is neither handled nor declared in the place from where its called ( main() method here). Hence you get a Compiler error . eat() of Frog class is called at runtime but befor that
compiler checks the method in the class of the reference type which is Animal here

[Neil Muya]

Ow okay , Got it . Thank You Simran!

[Jeevan Reddy]

Simran Dass wrote:

Compiler checks the reference type of the variable. In case of overriding which method
will be called is decided at runtime. In the line :

Animal a = new Frog();

Compiler sees that a is of type Animal . But the eat() method in class Animal throws Exception
which is neither handled nor declared in the place from where its called ( main() method here). Hence you get a Compiler error . eat() of Frog class is called at runtime but befor that
compiler checks the method in the class of the reference type which is Animal here

Thanks for the info Simran. That helped me too.