how to run a jar file from the cmd prompt using a specific jre version

Hi All,

I am facing an issue where I need to run a jar file from cmd.
This jar was compiled using jdk 1.5.The server from where I run this jar file has jdk 1.4 and jre 1.4 set in the path.

I don't have the necessary permissions to modify this path from the environmental variables because of business issues.

I tried to set the path from cmd prompt using the below command

set path=%path%; "C:\Program Files\Java\jre1.5.0_05\bin"

now when I check the version of the java jre again it still shows the older version 1.4

I cannot override the path variable using

set path="C:\Program Files\Java\jre1.5.0_05\bin"

as it affects the other variables.

Please can someone help me with a workaround for this issue so that I can run the jar from cmd while at the same time run it using jre1.5?Is there any such command which allows setting the jre version at the same time while running the jar?

Many Thanks in advance!

Moieen

set path=%path%; "C:\Program Files\Java\jre1.5.0_05\bin"

Change to

set path="C:\Program Files\Java\jre1.5.0_05\bin";%path%

Thanks Deepak!

The issue seems to be resolved

Best Regards

Moieen

Moieen Khatri wrote:Thanks Deepak!

The issue seems to be resolved

Best Regards

Moieen

The cause, in case any one stumbles on this thread later, is that another JRE was in the path and the OS always picks the first matching java.exe from the path

Hi Deepak,

Thanks for the explaination of the cause.

It was very helpful for me

Best Regards,

Moieen

Also you can just restrict java version:
java -version:"1.6*"

Welcome to the Ranch

If we are reopening old threads, I shall add my tuppenceworth: you can quote the direct path to the java executable:
"C:\Program Files\Java\jre1.5.0_05\bin\java" MyClass

Because there is a space in “Program Files”, you will probably have to enclose the first part of that instruction in "quotes".