get application filepath

[Allasso Travesser]

Hello,

Is it possible and how to get the full filepath of a currently running Java application?

something analogous to $0 in a UNIX script?

Thanks, Allasso

[Henry Wong]

Have you tried the "user.dir" property from the Systems class?

Henry

[Rob Spoor]

That's not necessarily the same; user.dir is the folder from which the JVM was started.

Do a search; this question has come up before. In short, you can't get this path directly, but there are some tricks. One uses ProtectionDomain (do a search on Javaworld.com), one uses Class.getResource() using the class itself. For example, in class Test:

URL url = getClass().getResource("Test.class");
// use this to get the base URL, then convert that to a file if possible

[Allasso Travesser]

Rob Prime wrote: In short, you can't get this path directly, but there are some tricks. One uses ProtectionDomain (do a search on Javaworld.com), one uses Class.getResource() using the class itself. For example, in class Test:

URL url = getClass().getResource("Test.class");
// use this to get the base URL, then convert that to a file if possible

Thank you, Rob, yes, they both work.

I found this on Real Gagnon's site this morning demonstrating getProtectionDomain as you said:
http://www.rgagnon.com/javadetails/java-0581.html

URL url = getClass().getProtectionDomain().getCodeSource().getLocation();

getProtectionDomain() will throw a security exception however if the security manager doesn't allow it.