throw assertion error

[Heba Mahmoud]

  
public class TestThrow {
	
	
	static void test() throws Error{
		
		if (true) throw new AssertionError();
		System.out.println("test super class");			
	}
	
	public static void main(String[] args) {
		
		try {
			test();
		} catch (Exception e) {
			System.out.println("exception");
		}
		System.out.println("enddd");
	}

}
  

what will be the output ?
a throwable is throwen by main
or an exception is throwen by main

[Wouter Oet]

What has the output when you ran it?

[Heba Mahmoud]

the output is
Exception in thread "main" java.lang.AssertionError

i know that error can't be handle by exception handler. but what i understand from output that the assertionerror is an exception
that means that it is may be a child for excepton class so why catch clause fails to handle.

and also ....at the same time i wondered why it cause an excption not an error

[Wouter Oet]

java.lang.AssertionError is a Child of java.lang.Error and not of java.lang.Exception and because of that it is not caught in your catch-block.

[Heba Mahmoud]

so the right answer will be a throwable is thrown by main

thanks

[Harpreet Singh janda]

Saying specifically it will be an Error not throwable. But because throwable is parent of both Error and Exception so in case of both you can say that if is a throwable but actually it will be Error or Exception.

[Rajeev Trikha]

Error and RuntimeException are unchecked exceptions so the compiler doesn't care whether you catch them, declare them or ignore them. Changing line 15 on your code to say (Error e) will bear out what Wouter has said.