This week's book giveaway is in the OCAJP 8 forum. We're giving away four copies of OCA Java SE 8 Programmer I Study Guide and have Edward Finegan & Robert Liguori on-line! See this thread for details.
this output 5 as after ++y ,y become 2 then add to it y++ where y =2 in that case then 2+2 =4 then increment y to be 3 then add the left hand side operands of y to have y=y+4= 3+4= 7
??? that what i understand but i don't know how 5 is the output ??
also try to test the same code changing y to int y=0; and see the result that =2
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1) Precedence Order: When two operators share an operand, the operator with higher precedence goes first.. I think, you know that!
2) Associativity : When two operators with the same precedence the expression is evaluated according to its associativity.
For Ex :
is treated as
Since = operator has right to left associativity.
3) Order of evaluation : In Java, the left operand is always evaluated before the right operand. also it applies to function arguments.