method invocation

[jose chiramal]

I have two classes Test1 and Test2:

public class Test1 {

public void doFooStuff() { }

}

public class Test2 extends Test1
{
public void doTest2Stuff() {


}

Test2 t2 = new Test2();
t2.doTest2Stuff(); // syntax error..




public static void main(String args[])
{
System.out.println("inside the main methjod");

}
}

Can someone please let me know why it errors. If i mention Test2 t2 = new Test2();
t2.doTest2Stuff(); inside main() or inside doTest2Stuff() it doesnt error.

Thanks..

[Devaka Cooray]

You are getting an error on that statement because it doesn't belong to a scope. Statements should reside in a scope - inside a method, constructor, or an initialization block. Please UseCodeTags when you post a code. It's unnecessarily hard to read the code otherwise.

[pankaj vijay]

jose a method execution starts from main method not from else where.

you are writing code that can not be reached from anywhere that's why its is showing error