value of instance variable in super vs sub class

[R Srini]

Hi all. I saw this question on Java Inquisition (http://enigma.vm.bytemark.co.uk/inquisition/index.php/Main_Page):

class superb {
	int x = 1;
	static int x2 = 2;
}

class test extends superb {
	int x = 3;
	static int x2 = 4;

	public static void main(String[] args) {

		superb st = new test();
		System.out.println(st.x + " " + st.x2);

	}

}

Question: What will the above code print? I was thinking that st.x would be 3 since x is a member variable. But its not. Can someone please help me understand why? TIA.

[Ankit Garg]

Access to instance variables is not polymorphic like non-static methods. It works just like static methods (this might help)....

[saima kanwal]

only instance methods are overridden , variables are never overridden. the st is superb type variable so it gets the value of x in superb class. it does not check what instance is in st variable.

[R Srini]

Thank you for the clarification, guys!