how to add number of digit in array

please help me out

what i want is ...

1.user enter no of digit of tat number
2.thn use enter tat number

so i want to store tat number in array..
please help me out i try some code but unable to do

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

// addition of digits to array

public class test {
public static void main(String str []) throws NumberFormatException, IOException
    {   
	      System.out.println("Enter no of digit of number");
	      BufferedReader b = new BufferedReader(new InputStreamReader(System.in));
	      int number= Integer.parseInt(b.readLine());
	          
	      int array_hold []= new int [number-1];
	      
	      System.out.println("Enter number");
		   BufferedReader c = new BufferedReader(new InputStreamReader(System.in));
		      int number_user= Integer.parseInt(c.readLine());
          // addition of digits of number in array 
	      
	      for(int i=0;i<number;i++)
	      {     int num1,num2;
	               num1=(int)Math.pow(10, number-(i+1));
                    num2=(int)Math.pow(10, number-(i+1)-1);
                    
                    int rl=(int)number_user%num1;
                    array_hold[i]=(int)rl%num2;
                    
	      }
	      
     	     for(int num:array_hold)
             System.out.println(num);
    }
}

>

the final time through the loop,

always evaluates to zero

so num2 ends up being zero and this causes a division by zero error when you say

Tim McGuire wrote:the final time through the loop,

number-(i+1)-1

always evaluates to zero

so num2 ends up being zero and this causes a division by zero error when you say
array_hold[i]=(int)rl%num2;

so how we can resolve this problem???

You could loop one less time and handle outside the loop or set an if statement inside the loop to take care of the last entry.