Validating an Int array

[jin kazama]

I am trying to validate an array of int data to check if the number is a certain number, ie. a mobile number 0 7 7 7 1 8 7 6 5 4 3.

So far the only way I can do this is to iterate through the array and check if each value matches one of the above numbers, eg.

(arrayInts[x] == 1) || (arrayInts[x] == 2) || (arrayInts[x] == 3) etc...

{
return true;
}

Can I ask for advice on a better way of accomplishing this?

[Henry Wong]

How about instead of hardwiring the number, simply have a method that compares two arrays? And you can also use a loop too.

Henry

[Ragav Baskaran]

How about pushing the Integers in a ArrayList<Integer> and call its contains(obj) method to find the match ?

Thanks,
Ragav.

[Rob Spoor]

Henry Wong wrote:
How about instead of hardwiring the number, simply have a method that compares two arrays?

It already exists: java.util.Arrays.equals(int[], int[]).

[jin kazama]

Thank you all for your advice with this task.

I have looked at the equals method and would I be correct if it returned true if the two objects were the same, in this case the two arrays would have to have the same numbers in the same order for it to return true?

I have created a new int array:

int[] validNumbers = {0,1,2,3,4,5,6,7,8,9};

but now I am struggling to have the method iterate through both arrays.

[Syed Ullah]

I'm still not quite sure what you are trying to do here. Can you elaborate with some examples?

Why are you defining an array with 0-9 digits. Also, why did you use the OR(||) operator in your
comparison? Should it not be the AND(&&) operator?

[Henry Wong]

jin kazama wrote:
but now I am struggling to have the method iterate through both arrays.

In pseudo code....

    boolean is_equal (array1[], array2[]) {
        if (size of array1 != size of arra2) return false;

        for (index from zero to last element of array) {
             if (int at index for array1 != int at index for array2) return false;
        }
        return true;
    }

[Campbell Ritchie]

Welcome to the Ranch Syed Ullah.

Sorry for not noticing you earlier; had a busy day yesterday.