can you please explain the output of this program?

[shoeb sayyed]

public class Test {


	
	public static void main(String[] args) 
	{
	 StringBuffer b= new StringBuffer("abc");
	 StringBuffer c=new StringBuffer("def");
	 operate(b,c);
	 System.out.println(b+" "+c);        //but here c has "def" what happens exactly?
	}
	static void operate(StringBuffer b, StringBuffer c)
	{
		b.append(c);                       //b gets the value "abcdef"
		System.out.println(b);
		c=b;                                  //what happens over here? c should have "abcdef" too, right?
		
	}
}

[Baiju Scariah]

StringBuffer c=new StringBuffer("def");

and

"StringBuffer c" in "static void operate(StringBuffer b, StringBuffer c) " are not same.

When you call "c=b;", value of b is assigned to the temporary varibale, not to the c created in main().

So, if you print c in operate, result will be "abcdef", in main as it is not modified (only its copy is modified) it would print "def"..

Good to spend some time understanding differences between String & StringBuffer and concepts of pass by value & pass by reference..

[shoeb sayyed]

thanks Baiju,

It was really helpful for me