I need to help with the question 13 chapter 2

[Mauricio Archbold Babroza]

why is the result "furry bray" and is not "furry generic noise"???

3. class Mammal {
4. String name = "furry ";
5. String makeNoise() { return "generic noise"; }
6. }
7. class Zebra extends Mammal {
8. String name = "stripes ";
9. String makeNoise() { return "bray"; }
10. }
11. public class ZooKeeper {
12. public static void main(String[] args) { new ZooKeeper().go(); }
13. void go() {
14. Mammal m = new Zebra();
15. System.out.println(m.name   m.makeNoise());
16. }
17. }

[Harpreet Singh janda]

Because members variables never inherited and do not behave in polymorphic way.

Both the classes have variable with same name and you are assigning a child reference to parent object. So the instance member of the referring (Parent class) class will be called and method of the original underlying class (Child class) will be called.

[Devaka Cooray]

Mauricio Archbold Babroza wrote:I need to help with the question 13 chapter 2

Is it from K&B Study Guide? Please quote the source properly.

[pankaj vijay]

there is one very simple rule about this: Methods are called based on object while static methods & members variables are called based on reference.
Now you wrote

 Mammal m = new Zebra();     

here reference is of Mammal while object is of Zebra so

  m.name 

will call Mammal variable &

m.name  

will call zebra noise method

[Harpreet Singh janda]

will call Mammal variable &
view plaincopy to clipboardprint?

  m.name 

m.name will call zebra noise method

i think you want to say

   m.makeNoise()  

[Jim Hoglund]

Yep, for sure. I changed makeNoise() to static in both classes,
as demanded by the compiler, and the output became, "furry
generic noise." Mauricio Archbold Babroza, are you there?

Jim ... ...