luby transformation

can any body please help me to implement luby transformation code using java?

Hi Vinay,

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Do you have the algorithm for that? If not, find a source for it. If yes, what concrete issues are you encountering?

the algorithm is:

1.We have to select a word like: "hello"
2.convert this string into binary form.like "hello" binary form will be 10011100 10010101 10011100 10001010 10101001
3.take each binary form as m1,m2,m3,m4 and then perform XOR operation between them,like m1 xor m2 ,m2 xor m3, m3 xor m1,m1 xor m2 xor m3.
3.then print the result.

i have apiece of code here but using it i cud only convert a word into binary but not able to perform XOR operation. please Ulf help me!

import java.io.*;

public class Main {
 
 public static void main(String[] args) throws Exception{
new Main().doit();
}

public void doit() {
String s3 = "hello-srmis-dance";
System.out.println(s3);
String [] temp = null;
temp = s3.split("-");
dump(temp);
}

public void dump(String []s) {

for (int i = 0 ; i < s.length ; i++) {
//System.out.println(s3);
}

byte[] bytes = s[0].getBytes();
 StringBuilder binary = new StringBuilder();
 for (byte b : bytes)
 {
    int val = b;
    for (int i = 0; i < 8; i++)
    {
       binary.append((val & 128) == 0 ? 0 : 1);
       val <<= 1;
}
    binary.append(' ');
 }
 
 byte[] bytess = s[1].getBytes();
 StringBuilder binarys = new StringBuilder();
 for (byte b : bytess)
 {
    int val = b;
    for (int i = 0; i < 8; i++)
    {
       binarys.append((val & 128) == 0 ? 0 : 1);
       val <<= 1;
}
    binarys.append(' ');
 }
 
 byte[] bytes1 = s[2].getBytes();
 StringBuilder binary1 = new StringBuilder();
 for (byte b : bytes1)
 {
    int val = b;
    for (int i = 0; i < 8; i++)
    {
       binary1.append((val & 128) == 0 ? 0 : 1);
       val <<= 1;
}
    binary1.append(' ');
 }
 System.out.println("******************************");

System.out.println(s[0] + " " + "is " + binary);
System.out.println(s[1] + " " + " is " + binarys);
System.out.println(s[2] + " " + " is " + binary1);
System.out.println("******************************");

}
}

Are you familiar with the XOR operator in Java? It's "^", and searching for "bitwise logical operators java" should find more info about it.

You're asking the same question here.