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It is because i believe this conversion is taking place at compile time rather then at run-time as variables are declared final.
As they are within the range of the byte, that is why it is not giving any compilation error. Lets say
It will start giving compile time error as it has gone out of range. But above conversion i suppose is happening at compile
time rather then at run-time. I would love if someone else will comment.
In the second case, both s and s1 are compile time constants. This means that the compiler knows their value at compile time. So when you say s+s1, the compiler is able to find the result of that expression i.e. the compiler knows that s+s1 will be 20, so it replaces the expression by its value. So your code after compilation becomes