Comparable Interface

[rahulJ james]

I am writing a program to get the numbers from the user and get that sorted based on ODD or EVEN numbers. I am using a list to store the numbers from user and I could sort it. Can I do the same by using Comparable Interface. If Yes, can someone helo in this..

   
class sorting{
     public static void main(String args[])
     {

         InputStreamReader istream = new InputStreamReader(System.in) ;
          BufferedReader bufRead = new BufferedReader(istream) ;
          int i=0;
          int j=0;
          int k=0;
          int even[]= new int[15];
          int odd[]= new int[15];

         try{
			 System.out.println("Enter the  integer");
          	while(i<20){

          	int firstName = Integer.parseInt(bufRead.readLine());
          	if(firstName % 2==0){
          		even[j]= firstName;
          		j++;
			}
			else
			{
				odd[k]= firstName;
				k++;

			}
			i++;
}
           Arrays.sort(even);
           Arrays.sort(odd);
            		}
        catch (IOException err) {
               System.out.println("Error reading string");
   		}

     }
}
 

[Sridhar Santhanakrishnan]

Check out Collections.sort()

[rahulJ james]

This doesnt give me a proper order.. Again it sorts by its own way..

[Rob Spoor]

Really? Because if I use your code and then print out the two arrays, I get two sorted arrays - with leading zeros for all non-set elements of course.