object array?

[Prasad Kharkar]

I found this code on certPal
I wanted to know how come the compiler compiles the code fine even if we are missing the array brackets for the object ?

# public class ID  {  
       
     public static void main(String... args)  {       
         Object[] object = new String[5][5];     // here we are declaring single dimensional array and defining two dimensional array, how is it possible?
         int counter = 0;     
         for(Object o : object) {  
             System.out.println(o);  
             counter++;     
         }           
         System.out.println(counter);     
     }     
 }           

[Dejan Miler]

Hi.

We didn't miss anything here.
When we initialize array of object (or primitives) thy are initialized with theirs default value.

Hope that this was helpful

[Prasad Kharkar]

no no
I wanted to say
here
we are defining 2D array that means there should be [][] isn't it but in the declaration there is only [] so why doesn't it give compiler error?

[Prithvi Sehgal]

Hello,

Please Prasad, use meaningful subject lines. Please check MeaningfulSubjectLine

It is because it is an Object and anything is an Object in java. Be it two dimensional or one dimensional,
it doesn't matter. It can be assigned to Object. If you amend your code to something like this

  

String[] myArray = new String[5][5];

It will give you a compile time error.

Hope this helps,

[Rajeev Rnair]

Adding to that an Array is an object in Java.
So String[] is an Object.
String[][] is an Object[]

hope this is clear!

[Prithvi Sehgal]

Rajeev Rnair wrote:Adding to that an Array is an object in Java.
So String[] is an Object.
String[][] is an Object[]

hope this is clear!

Pretty meaningful pointers Rajeev.

Best Regards,

[Rajeev Rnair]

Thank you Prithvi

forgot to add; String[][] is an Object too .

[Prithvi Sehgal]

You are welcome CowBoy
When is your exam?

Best Wishes,

[Prasad Kharkar]

thanks prithvi and rajeev
got it now