This creates a new ValHold() and assigns to v; so v.i is 10.
second one prints local variable "i" and it is "0"
This method is trying to assign a new reference to the passed one. However it CANNOT change the original reference "v". But the "v.i = 20; " is still valid because the calling method can change the values of member variables (but not the reference). So the third one prints 20.
hi Shaid
lets start with main method first and lets see the flow of control.
ObParm o = new ObParm();
o.amethod();
we know what happened above.
now in amethod
int i = 99; is creating a local variable of this method.
then v object of valhold is created
then v.i=30;
mean the i of v object has been changed to 30 as it is public. this dosnt mean the local variable of amethod is 30, that is still 99.
now another method is called. so the rest of code will follow only after the complete execution of another method.
in another method
i=0; is done which is of no use.
now the another method was passed an object v
code is changing v.i to 20 that mean before in amethod when it was changed to 30 is changed to 20 now.
another object of vhal is created that is vh
and vh is coppied to v.
now
v no more holds the previous object. now it is reffereing to new object . which was created recently.
so according to vhal the new object's i data member shud be 10
so when next print of v.i is executed it gives 10
then value of i
which was changed to 0
so we have now
100
now amethods last statment is executed that is v.i which was last changed to 20.
as v=vh wont be valid in this block. v was refrence in another