well this is a little bit difficult to guess but I think this is the best way to do this
we are given 4 compound operators and we have to use them exactly once
now given that we want output as 33 and x =7 and y = 2
we have to give just trial and error to this
33 is big as compared to 2 and 7 and hence we will use *= operator first
and also we have to use only 2 x we will use them all in this line only
this gives x = 49
now we have to reduce the answer by 16 to get 33
what do we have now?
4 y's , 2 *= and one -=
we can achieve 16 by
now y is 4
now it is 16
as we have x = 49 and y = 16
we can write
this gives 49-16 = 33
SCJP 6 [86%] June 30th, 2010
OCPWCD [84%] March 26th, 2013
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There is no straight forward technique for solving this kind of problem. I consider
myself lucky to have spotted how the elements might fit together in a reasonable
amount of time. But it could have taken for ever. What helped was to "fiddle" with
the given information on paper, play what-if mind games and draw pictures. There
were constraints in both the fill-in template and the cut-and-paste elements. I know
that this may not be very helpful, but it's all I have to offer.
That one was a little TOO puzzle-y. We were trying to sort of emulate a drag and drop question, but none of the real D&D questions are that puzzle-y. So I'd say don't spend too much time on that particular question.
Spot false dilemmas now, ask me how!
(If you're not on the edge, you're taking up too much room.)