This week's book giveaway is in the Mac OS forum. We're giving away four copies of a choice of "Take Control of Upgrading to Yosemite" or "Take Control of Automating Your Mac" and have Joe Kissell on-line! See this thread for details.
Which is correct? (Choose all that apply.)
A. As the code stands it will not compile
B. As the code stands the output will be 2
C. As the code stands the output will be 3
D. If the hashCode() method is uncommented the output will be 2
E. If the hashCode() method is uncommented the output will be 3
F. If the hashCode() method is uncommented the code will not compile
ans is :C ANd D
i think answer should be C and E
hasCode() determines the bucket,so all object would be placed in the same bucket.
Map can hold duplicate entries
and as far i know equals is used so that when we use the
get function to retrieve the data ,the passed object is same as which we
used in the