What is the output for the below code is different?

[thejaka samarakoon]

What is the output for the below code ?

    
public class Test {
    
    public static void printValue(int i, int j, int k){
        System.out.println("int");
    }
    public static void printValue(byte...b){
        System.out.println("long");
    }
    
    public static void main(String... args) {
        byte b = 9;
        printValue(b,b,b);
    }
}

Why in this program int is printed rather than long? Can anyone explain.

[rushikesh sawant]

method with var-arg is selected only if there is no other valid overload. You should read method overloading section.

[thejaka samarakoon]

rushikesh sawant wrote:method with var-arg is selected only if there is no other valid overload. You should read method overloading section.

thanks

[Abimaran Kugathasan]

Var - args is added to Java in JDK 1.5, but widening is there long before, so they did like this. Widening > Boxing > Var - Args. This is the priority order!