How to iterate a Set (2 steps once)

[Andrei Antonescu]

Hello,

Can you please tell me if there is any way of iterating over a Set making 2 steps at once?
I would like the equivalent of :

for(int i=0;i<=arraylist.size();i=i+2) {..}

but for a Set collection.

Thanks in advance

[fred rosenberger]

what's wrong with using an iterator, and just calling next() twice?

[Rob Spoor]

Of course ensuring that there is an even number of elements, or by checking hasNext() before calling next again.

[Hunter McMillen]

Every element in a Set is distinct, so my question is why would you be skipping over elements? And if the elements don't matter why cant you just use an array?

Hunter

[Campbell Ritchie]

If you have named your variables correctly, you are not iterating a Set but a List.

[David Newton]

"equivalent of"

[Campbell Ritchie]

David Newton wrote:"equivalent of"

Yes, I missed that. But Fred has already given a good answer.

[Andrei Antonescu]

Hello,

Thank you all for your replies. I will call next() twice.

[Campbell Ritchie]

Maybe better to try this

 . . .
it.next();
if (it.hasNext())
{
  it.next();
}
 . . .

Otherwise you may suffer an exception.

[Rob Spoor]

That's what I already said.

[Campbell Ritchie]

Rob Prime wrote:That's what I already said.

Yes, but I only ever notice your posts when they are 5 seconds ahead of mine, not 3 days