K&Bs Book tells me on Page 36:
Once a Subclass-outside-the-package inherits the protected member, that member (as inherited by the subclass) becomes private to any code outside the subclass, with the exception of subclass of the subclass.
here,m is protected member of AClass that is inherited by BClass.so,by above statement m in BClass would be Invisible outside BClass.
but ,it is accessible in Test.java
AFAIK this happens:
1) Compiler indeed does not see inherited protected method m() in package B (BClass).
2) Therefore compiler looks at superclasses and finds protected method m() as defined in package A (AClass). Compiler is happy with that because its the same package as the "caller".
3) Runtime behavior was in my original example (http://www.coderanch.com/t/504882/java-programmer-SCJP/certification/Modifier-protected-does-not-hide) different, but in this example the JVM has only one choice as well: m() from AClass.
Maybe K&B should go a little bit more in detail on page 36...