Do cast from int to short

[André Asantos]

Hi there, please could you see my code and tell me why I must also do cast of rangeDe5NumeroNoMaximo attribute
because that atributte also short typed...

//cast from int to short
	public static void main(String[] args) {
		int rangeDe10NumerosNoMaximo = 1234567891;
		short rangeDe5NumeroNoMaximo = 12345;
		short resultado = (short) (rangeDe5NumeroNoMaximo + (short) (rangeDe10NumerosNoMaximo));
			System.out.println(resultado);
	}

thanks,
André AS
SP - Brazil

[David Newton]

http://java.sun.com/docs/books/jvms/second_edition/html/Concepts.doc.html#16021

[André Asantos]

Hello to you David,

I joined your web link...

I read that the default value of long is 0L, ok but I can't use it right? Look at:

public static void main(String[] args) {
		long longTipoPrimitivo;
			System.out.println(longTipoPrimitivo);
		}

That shows compile-time error, why?


André AS
São Paulo - Brazil

[André Asantos]

Should not that print their default value?

[David Newton]

http://java.sun.com/docs/books/jls/second_edition/html/defAssign.doc.html#25979

[Jesper de Jong]

André Asantos wrote:Should not that print their default value?

Local variables inside methods, as you show in your example, do not have default values. You must initialize them to a value before you use them.

Only member variables (at the level of a class) are initialized with default values (0L in the case of a long).