simple doubt - Java logic using false and true

[André Asantos]

hi,

why did that print false?

boolean x = false;    
boolean y = true;    
System.out.print(x && y); 

and that true?

 x = false;  
 y = true;  
 System.out.print(x && y);  

[Christophe Verré]

and that true?

Are you sure ??

[Joanne Neal]

Th only difference between those two is that we can't see how you declare x and y in the second one, although I can't imagine any declaration that would cause it to print true.
Why don't you show us how you are declaring x and y and how you are calling these two pieces of code.

[Virendrasinh Gohil]

I tried. It printed false both the time.

[David Newton]

André Asantos wrote:why did that print false?

Because it's false.

and that true?

It didn't.

[Vishal Kashyap]

André Asantos wrote:hi,

why did that print false?

boolean x = false;    
boolean y = true;    
System.out.print(x && y); 

and that true?

 x = false;  
 y = true;  
 System.out.print(x && y);  

Because, the truth table of two variable x and y will be true if and only if both values are true. that's why your first code prints false.

but, as we can see; you have not clearly shown declaration statement. So, we could not understand you here.

[Vinoth Kumar Kannan]

Vishal Kashyap wrote:...but, as we can see; you have not clearly shown declaration statement...

Anyway does the declaration statement really matter? (x && y) immediately follows clear boolean assignments to x and y. 'false' can be expected only when there is something else between the assignment and the expression.

[David Newton]

The point is we don't *know* what's there--the two chunks could be completely unrelated and in different files, or there might be no separation between the two chunks at all. Since the claim that the behavior of boolean "and" is broken, there's obviously more information needed, because it's extremely unlikely "and" is broken.