switch statement and compile time constatns.

[Jan Osykowski]

Hey guys,

I have a question about the switch construction. In the book it's written that the case constant must be a compile time constant and thus i have a question to this code:

int x = 5;
		int a = 4;
		final int b = 4;
		switch(a) {
			case b + 2*b:
		}    

And it works but I think that b+ 2*b is not a compile time constant. What do you think? On the other hand this code doesn't work:

int x = 5;
		int a = 4;
		final int b = 4;
		switch(a) {
			case b + x:
		}    

Why it's like this?

Cheers,
Jan.

[Seetharaman Venkatasamy]

Actually, if you mix your compile time constant with non-compile time constant then result become non-compile time constant

[Malatesh Karabisti]

Compile time constant will be formed only with Rules

[Jan Osykowski]

Alright, thanks for the answers!