Threads Doubt

[Gari Jain]

class RunTest{
public static void main(String args[])
{
Runnable r = new Runnable() {
 public void run() {
 System.out.print("Inside Runnable Subclass");
 }
 };
 Thread t = new Thread(r) {
 public void run() {
 System.out.print("Inside Thread's subclass");
 }
 }; 
t.start();
}}

OUTPUT-Inside Thread's subclass
possible reason for this beahviour(Correct me If I am wrong):
In the start function, from where run is called there is no information about the implementer of Runnable created?
OR
The run() inside the Thread's subclass is overriding the Runnable implementer's run?But how can Thread's subclass overrides Runnable implementer's run?

[Anton Brass]

If you have a look in the Source Code of the Class Thread you see following method:

    /**
     * If this thread was constructed using a separate 
     * <code>Runnable</code> run object, then that 
     * <code>Runnable</code> object's <code>run</code> method is called; 
     * otherwise, this method does nothing and returns. 
     * <p>
     * Subclasses of <code>Thread</code> should override this method. 
     *
     * @see     java.lang.Thread#start()
     * @see     java.lang.Thread#stop()
     * @see     java.lang.Thread#Thread(java.lang.ThreadGroup, 
     *          java.lang.Runnable, java.lang.String)
     * @see     java.lang.Runnable#run()
     */
    public void run() {
	if (target != null) {
	    target.run();
	}
    }

Since you override run() this code won't ever be executed. Instead your run method is called and print yout defined output

[Gari Jain]

Got it.

Thankx a lot.