Initialization blocks in java

[dileep keely]

In general:
1))static variable is intialized before an instance is created.
2)once a class is loaded the static blocks run
3)initialization blocks run after instance is created

class Temp
{
a=10;
static 
{
int a;
System.out.println(a);
}
public static void main(String[]args)
{
//Temp t=new Temp();
}}

In the above case my understanding is :

a-->is given a default value
a-->is assigned with a value 10

But this is not happening,I get an error as (identifier expected)
I am missing an importantinformation,please help me out.

[Vijitha Kumara]

Firstly, please UseCodeTags when posting the code... You are defining "a" inside the static block hence not accessible from outside the block.

[dileep keely]

<updated with code tags>
but,why is that the default value is not assigned for a.

class Temp
{
[strike]//a=10;[/strike]
static   
{  
int a;  
System.out.println(a);  
}  
public static void main(String[]args)  
{  
//Temp t=new Temp();  
}
}

ERROR:java:6: variable a might not have been initialized
system.out.println(a);

[Vijitha Kumara]

dileep keely wrote:...but,why is that the default value is not assigned for a...

Only instance and class variables are automatically initialized to default values, but not local variables.

[John Eipe]

During compilation, it requires variable declarations before definitions.

[Rob Spoor]

Your "a" is a local variable of the static block. I think you want to swap two lines:

class Temp   
{   
    int a;   

    static    
    {   
        a=10;   
        System.out.println(a);   
    }

[Abimaran Kugathasan]

Have a look on this

[dileep keely]

No,I don't want to swap the above two lines.Because a non- static variable can't be referenced from the static .

[Rob Spoor]

Then make it static.

[Campbell Ritchie]

Or: why have you got a static block in the first place?