How does the % operator work?

[Ethan Bauer]

  odd = !( number % 2 == 0 );  

Could anyone explain how you use % as a logical operator?
Maybe another example is better but this was the one I found in the course I'm taking on Java..

[Wouter Hermans]

% gets you the remainder of a division. In this case, a number is odd when the remainder is not zero when you divide it by two.

[Kr Manish]

number % 2 == 0 translates to : is the number an even number ? (hope you realize, if after dividing a number remainder is zero, it is even number)
but the *full* code snippet looks strange to me. Value of odd will be false when number is even, and vice versa. wonder what the code does, though.

[Campbell Ritchie]

There is a neater way to do it

boolean odd;
 . . .
odd = number % 2 != 0;

Because the % operator has a higher precedence than !=, you don't need any (round brackets).

There is a quicker way to do it

boolean odd;
 . . .
odd = (number & 1) != 0;

Note that the & operator will give much faster performance than % because it is simply comparing bits, not dividing, but the (round brackets) are needed here. I shall leave the reader to work out how it works, and also to work out which range of operands it will work for.

[Campbell Ritchie]

And welcome to the Ranch , Wouter Hermans.