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simple proof make your mind mad

Arun Giridharan
Ranch Hand

Joined: Sep 30, 2010
Posts: 290

Start with: -20 = -20
Which is the same as: 16-36 = 25-45
Which can also be expressed as: (2+2) 2 (9 X (2+2) = 52) 9 X 5
Add 81/4 to both sides: (2+2) 2 (9 X (2+2) + 81/4 = 52) 9 X 5 + 81/4
Rearrange the terms: ({2+2}) 9/2) 2 = (5-9/2) 2
Ergo: 2+2 - 9/2 = 5
Hence: 2 + 2 = 5

See... simple, isn't it?

i found this in some mathematical article ,i saved some others tooo
pete stein
Bartender

Joined: Feb 23, 2007
Posts: 1561
Arun Giridharan wrote:Start with: -20 = -20
Which is the same as: 16-36 = 25-45
Which can also be expressed as: (2+2) 2 (9 X (2+2) = 52) 9 X 5
Add 81/4 to both sides: (2+2) 2 (9 X (2+2) + 81/4 = 52) 9 X 5 + 81/4
Rearrange the terms: ({2+2}) 9/2) 2 = (5-9/2) 2
Ergo: 2+2 - 9/2 = 5
Hence: 2 + 2 = 5

See... simple, isn't it?

i found this in some mathematical article ,i saved some others tooo


Your equations as written don't make much sense to me. Could you clarify them a bit?

Usually I've found that similar problems are due to division by 0, but again, I can't follow your math to see if this is the case here.
Henry Wong
author
Sheriff

Joined: Sep 28, 2004
Posts: 19074
    
  40


I think that you may have copied it wrong, because some of your transitions don't make sense. You are missing operators with some, and you added parens around the equals that compare the both sides.

Henry


Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor)
Peter van de Riet
Ranch Hand

Joined: Apr 09, 2004
Posts: 112

-20=-20
16-36=25-45
4^2-36 = 5^2-45
4^2-36 = 5^2-45
4^2-2.4.9/2 = 5^2-2.5.9/2
4^2-2.4.9/2 +(9/2)^2 = 5^2-2.5.9/2 +(9/2)^2
[4-(9/2)]^2 = [5-(9/2)]^2
4-(9/2) = 5-(9/2)
4 = 5
2+2 = 5

I have made a picture for the correct formatting of the quotations above.
Between step 5 and 6 the following is applied a^2 + 2ab + b^2 = (a + b)^2



[Thumbnail for quotation.jpg]



Each number system has exactly 10 different digits.
Henry Wong
author
Sheriff

Joined: Sep 28, 2004
Posts: 19074
    
  40


This is actually a common trick (although not as common as divide by zero). The trick relies on the fact that the square root has a positive *and* negative result -- and basically obfuscates the fact that they are taking the positive number in one case, and the negative number in the other.

Henry
Ryan McGuire
Ranch Hand

Joined: Feb 18, 2005
Posts: 1013
    
    3
Henry Wong wrote:
This is actually a common trick (although not as common as divide by zero). The trick relies on the fact that the square root has a positive *and* negative result -- and basically obfuscates the fact that they are taking the positive number in one case, and the negative number in the other.

Henry


I'm curious...
We seem to see a handful of these "proofs" each year. Does anyone here still believe there are simple algebraic ways to prove that two unequal constants are equal?

I'll admit that sometimes it's a fun challenge to determine which one is the invalid step in a new "proof". I'm with Arun... this kind of thing may deserve a or maybe a , but I certainly don't think it deserves a , as some have gotten.

Joe Ess
Bartender

Joined: Oct 29, 2001
Posts: 8997
    
    9



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Joanne Neal
Rancher

Joined: Aug 05, 2005
Posts: 3742
    
  16
Joe Ess wrote:


Ryan McGuire wrote:I'll admit that sometimes it's a fun challenge to determine which one is the invalid step in a new "proof".


And the invalid step in that proof is that the quote is 'the love of money is the root of all evil'


Joanne
 
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