static method not running

[nirjari patel]

  public class LargeNum { 

	public int n1 = 10;
	public int n2 = 20;
	public int n3 = 30;
	public static int n4 = 40 ;
	public static int n5 = 50;


	public void go(int n1, int n2, int n3) {

		
		
		if(n1>n2){
			if(n1 > n3) {
				System.out.println("n1 is largest") ;
			}
			else {
				System.out.println("n3 is the largest");
			}
		}
		else {
			if(n2>n3){
				System.out.println("n2 is largest");
			}
			else {
				System.out.println("n3 is largest");
			}
		}

	}

	public void static stGo() {

		
				System.out.println("n1 is largest") ;
		
				System.out.println("n3 is the largest");
		
		
				System.out.println("n2 is largest");
			
				System.out.println("n3 is largest");
			
		}

	

	public static void main(String [] args)	{

		/* public static int n4 = 40 ; 

		n4 = 40; */

		n5 = 500 ;

		LargeNum ln = new LargeNum();

		ln.go(ln.n1, ln.n2, n5) ;
		System.out.println(n5);

		
	}
}

When I try to compile this code, I am getting following output.

LargeNum.java:33: <identifier> expected
void static stGo() {
^
LargeNum.java:33: '(' expected
void static stGo() {
^
LargeNum.java:33: invalid method declaration; return type required
void static stGo() {
^
3 errors

1) Why is this static method not working ?

2) Can I declare static variable inside main() ? Its not working here.

Thanks

[Dhruva Mistry]

Hi Nirjari,

Your code for static method is

public void static stGo() { 

which doesnt fulfil the syntax of a java method it should be like,

<access&non-access modifiers> <return-type> <method-name>

which can be fulfilled by putting the return type : "void" right before the method name. like,

 public static void stGo() {

and, public n static - access modifier/control
void - return type of a method

[nirjari patel]

Oh, so order is also important. I thought, if you change the order , it will not be a problem.

Thanks

[Dhruva Mistry]

else compiler interprete this way : "method returning type is static object/variable"

[Rob Spoor]

nirjari patel wrote:Oh, so order is also important. I thought, if you change the order , it will not be a problem.

Thanks

Order is not important, except for a few. As said, the return type must come immediately before the method name. The method-generic type*, if present, must come immediately before the return type. Before that, any modifiers (public/private/protected, synchronized, static, etc) can come in any order.

* If you don't know what it means, don't worry. If you're still interested look up how generics in Java work.

[Adam Richards]

The original post seems to have been edited to remove syntax errors. However, the stGo() method will still not execute, because it's never called from anywhere (at least, not in the code shown).