yet another ArrayIndexOutOfBoundsException

[mrh Peshone]

	public static void main(String[] args) {
		try {
		int N = Integer.parseInt(args[0]);   // [b]ArrayIndexOutOfBoundsException[/b] What is it that is wrong? Thanks. g
		boolean[] a = new boolean[N];
		for (int i=2; i<N; i++) a[i] = true;
		for (int i=2; i<N; i++ )
			if(a[i] != false)
				for(int j=i; j*i<N; j++)
					a[i*j] = false;
		for(int i=2; i<N; i++)
			if(i>N -100)
				if(a[i])System.out.print(" " + i);
		} catch (NumberFormatException ex) {}
		System.out.println("/n");
	}
}

[Joanne Neal]

Are you passing any parameters to your program ? Args contains a list of the command line parameters, so if you don't pass any it will be empty.

[mrh Peshone]

public static void main(String[] args) {
		String[] args1 = { "101010101010" }; // that's the line, the actual error is "NumberFormatException" Thanks.
		try {
		int N = Integer.parseInt(args1[0]);

I guess I am passing the wrong argument!?

[Henry Wong]

George Peshone wrote:I guess I am passing the wrong argument!?

An integer ranges from -2147483648 to 2147483647. The number 101010101010 is outside of this range.

Henry

[mrh Peshone]

Yes, that was the case. Thanks much.