This week's book giveaway is in the OCAJP 8 forum. We're giving away four copies of OCA Java SE 8 Programmer I Study Guide and have Edward Finegan & Robert Liguori on-line! See this thread for details.
It's 5. Theoretically, that's because you don't have one String concatenation but two; s + "b" + "c" should be read as ((s + "b") + "c"). So the Strings:
- "ab" (from s + "b")
- "abc" (from s + "b" + "c')
In practice it's also 5 but because of another reason. The compiler turns String concatenations into a StringBuilder. I've compiled and decompiled (with JAD) your example, and this is the result:
That's still 5 objects:
- the StringBuilder - "abc", as a result of calling toString() on the StringBuilder
Every String literal is an object, so that's already three. I clearly see the word "new" there with the StringBuilder, so that's another one. And StringBuilder.toString() returns a new String object containing the same characters as the StringBuilder, so that's five.