How to add removal of newLine in a regexp pattern

[Andrew Carney]

Hello,

I have a long String coming from a different system that I am escaping using regexp using:

String pattern = "[^a-zA-Z0-9\\s]";
String[] title = item.getTitle().replaceAll(pattern,"").split(" ");

i.e. reserve only alphanumeric and white spaces.
The problem is that I still get the \n in the splitted array and I would like to remove it.
I can do a replaceAll("\\n", "") on each String in the array however would really prefer to do it in the original pattern before the split.

Any ideas...?

[Campbell Ritchie]

If I remember correctly, (but you can check here and here) line end characters count as whitespace (\s).

[Andrew Carney]

Uhmmmm so there is no way to around this other than going through each stringbin the splitted array...?

[Rob Spoor]

Check out the possible flags for java.util.regex.Pattern. I believe DOTALL is the one you need.

[Andrew Carney]

DOTALL flag did the trick, thanks!
I thought that since I am not using the dot in my regexp then it will have no effect but I guess it does

[Andrew Carney]

.