Largest and smallest number

[wei qi]

Hi everyone. I am trying to write a java program that allows the user to input as many integer values. At the end, it is supposed to figure out which is the largest and smallest number. -99 is used to quit if the user no longer wants to put in anymore values. Also, if -99 is entered in the first time, it will say "You did not enter any numbers". I wrote this code but am having a hard time getting it figure out which is the smallest.

import java.util.Scanner;
	
	public class BigAndSmall
	{
		public static void main(String[] args)
		{
		// Declare variables
		int min = 0;
		
		
		// Create a Scanner object
		Scanner keyboard = new Scanner(System.in);
		
		System.out.print("Enter an integer number or -99 to quit: ");
		input = keyboard.nextInt();
                int max = 0;
		int input = 0;
		
		// If value entered in the first time, -99, display message
		if (input == -99)
		{
			System.out.println("\nYou did not enter any numbers");
		}
                else
                {
		while (input != -99)
		{
		if (input > max)
		{
			max = input;
		}
		else if (input < min)
		{
			min = input;
		}
		System.out.print("Enter an integer number or -99 to quit: ");
		input = keyboard.nextInt();
		}
		System.out.print("\nLargest: " + max);

		System.out.print("\nSmallest:" + min);
		}
	}	
		
	

[Christophe Verré]

What do you want to express with "if (input != min) " ?

[wei qi]

i was just messing around. i'm a beginner to java. it should be "<"

[Christophe Verré]

Are you sure that initializing min and max to 0 will not cause any problem ?

[Jacob Coddaire]

Be sure to use the code button. It makes it easier to read.

import java.util.Scanner; 

public class BigAndSmall 
{ 
public static void main(String[] args) 
{ 
// Declare variables 
int min = 0; 
int max = 0; 
int input = 0; 


// Create a Scanner object 
Scanner keyboard = new Scanner(System.in); 

System.out.print("Enter an integer number or -99 to quit: "); 
input = keyboard.nextInt(); 

// If value entered in the first time, -99, display message 
if (input == -99) 
{ 
System.out.println("\nYou did not enter any numbers"); 
} 


while (input != -99) 
{ 
      if (input > max) 
      { 
           max = input; 
      } 
      else if (input <= min) 
     { 
         min = input; 
     } 
System.out.print("Enter an integer number or -99 to quit: "); 
input = keyboard.nextInt(); 
} 
System.out.print("\nLargest: " + max); 

System.out.print("\nSmallest:" + min); 
} 
}	

[Jacob Coddaire]

Can't you just do the following?

Instead of

else if (input <= min)

try this:

else if(input<min)
            min=input;

else
          min=min

[wei qi]

thank you for your reply!

i tried it and it still doesn't work.

i have a question about initializing min, max, and input. do i have to put int min(max,input) = 0? i feel that THAT is the problem but if i don't set it to a value it won't compile

[Christophe Verré]

There are several ways to initialize them :
1. Use Integer.MIN_VALUE and Integer.MAX_VALUE
2. Or, the first time the user inputs a value, initialize both min and max to that value

[wei qi]

how do you the 2nd? (first time the user inputs a value, initialize both min and max to that value)

[Christophe Verré]

After the first "input = keyboard.nextInt();", set both min and max to the input value.

[wei qi]

cheese and rice it works!! thank you!!

[Jesper de Jong]

Jacob Coddaire wrote:try this:

else if(input<min)
            min=input;

else
          min=min

min = min? Why would you ever want to assign a variable to itself?