web.xml url-pattern wildcards?

[James Hodgkiss]

My current servlet url is:
http://localhost:8080/MyWebApp/en/pp/login.html

How should I change my web.xml file so replacing "en" with any value would work? E.g.,
http://localhost:8080/MyWebApp/hk/pp/login.html
http://localhost:8080/MyWebApp/es/pp/login.html
etc.

My current web.xml snippet:

    <servlet-mapping>
        <servlet-name>LoginServlet</servlet-name>
        <url-pattern>/en/pp/login.html</url-pattern>
    </servlet-mapping>

Have tried the "*" wildcard, but with no success. If it's not possible, what other method can I use?

Thanks in advance,
James

[Jeanne Boyarsky]

James,
Besides listing them all? Can you change URLs to one of:
http://localhost:8080/MyWebApp/lang/en/pp/login.html
http://localhost:8080/MyWebApp/pp/en/login.html

[James Hodgkiss]

Hiya Jeanne,

Yes, I could change it to either of those. Do you have a solution based on that?

Thank you,
James

[Bear Bibeault]

Just map the prefix to a servlet, and within the servlet, use getPathInfo() to get the rest of the URL.

[James Hodgkiss]

Thanks. Like...

    <servlet-mapping>
        <servlet-name>LoginServlet</servlet-name>
        <url-pattern>/pp/Login/*</url-pattern>
    </servlet-mapping>

with urls http://localhost:8080/MyWebApp/pp/Login/hk.html and http://localhost:8080/MyWebApp/pp/Login/hk.wml

It works, but will be a pain changing all the dynamic link code...

[Bear Bibeault]

Yeah, the Servlet specification doesn't give us a whole lot of leeway in creating URL patterns with wildcards. We essentially get the choice of a trailing wildcard, or a filename wildcard.