exe file to get the property of the files in a folder

[Kaustubh G Sharma]

In java I need to create a launcher .. whose execution gave us the property details of files in a particular folder...how can i do this task?

[Stephan van Hulst]

Take a look at the java.io.File API.

[Wouter Oet]

What have you tried so far?

[Kaustubh G Sharma]

Nothing

[Kaustubh G Sharma]

yup finally i started something.......i created a program which got the name of all the files from the folder.....but how to get the properties of the files(basically all are dll files and want to read version, comments, description under version tab) and create a launcher of it is not done yet ... putting the code below please help me out..

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

package readigfileprop;

import java.io.File;

/**
 *
 * @author Gururaj Herle
 */
public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        File folder = new File("C:/READ");
    File[] listOfFiles = folder.listFiles();

    for (int i = 0; i < listOfFiles.length; i++) {
      if (listOfFiles[i].isFile()) {
        System.out.println("File " + listOfFiles[i].getName());
      } else if (listOfFiles[i].isDirectory()) {
        System.out.println("Directory " + listOfFiles[i].getName());
      }
    }
    }

}

[Wouter Oet]

Look at the java.awt.Desktop class. If allows you to launch the registered program for certain files.

[Kaustubh G Sharma]

Wouter Oet wrote:Look at the java.awt.Desktop class. If allows you to launch the registered program for certain files.

didn't get anything from it wouter

[Kaustubh G Sharma]

one code that i found is having some info of version tab which is mentioned on the top but not giving the hole information under item name option..pasting the code below... please take a look.....

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

package readigfileprop;

import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;

/**
 *
 * @author Gururaj Herle
 */
public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws InterruptedException, IOException, IOException {
        String dllFileName = "c:\\READ\\agrscoin.dll";
        File script = File.createTempFile("xxxxx", ".vbs");
        File result = File.createTempFile("xxxxx", ".txt");
        try {
            FileWriter fwrt = new FileWriter(script);
            fwrt.append("Set objFSO = CreateObject(\"Scripting.FileSystemObject\")\r\n"
                    + "Wscript.Echo objFSO.GetFileVersion(\"" + dllFileName + "\")");
            fwrt.close();

            Process p = Runtime.getRuntime().exec("cmd.exe /c"
                    + "cscript "
                    + script.getAbsolutePath()
                    + " >" + result.getAbsolutePath());
            int ret = p.waitFor();
            if (ret != 0) {
                System.out.println("Error :(  Exit code = " + ret);
            } else {
                BufferedReader rd = null;
                try {
                    rd = new BufferedReader(new FileReader(result));
                    String s;
                    while (null != (s = rd.readLine())) {
                        if (s.matches("^[\\d\\.]+$")) {
                            System.out.println("DLL version of " + dllFileName + " is: " + s);
                            break;
                        }
                    }
                } finally {
                    try { rd.close(); } catch (Exception ex) { }
                }
            }
        } finally {
            script.delete();
            result.delete();
        }
    }  

}

[Kaustubh G Sharma]

another option that I've found is to covert this dll files into text format and then can read all the version information from it... does it a proper way to do it... help me out

kaustubh

[Kaustubh G Sharma]

IS there any API which communicated with windows OS and get the required information for us or we should always try to use VB script or some other legacy code

[Rob Spoor]

Java does not provide this information, so you will need to either use JNI or call an external program.

[Darryl Burke]

Instead of the VBScript in the code you posted, try this:

fwrt.append("Set fso = CreateObject(\"Scripting.FileSystemObject\")\r\n"
      + "WScript.Echo fso.GetFileVersion(" + dllFileName + "\")\r\n"
      + "Wscript.Quit");

and get rid of the regex matching, it won't be needed.

//                        if (s.matches("^[\\d\\.]+$")) {   
                            System.out.println("DLL version of " + dllFileName + " is: " + s);   
//                            break;   
//                        }

edit And make sure to go through all sections of When Runtime.exec() won't.

[Kaustubh G Sharma]

Thanks Darryl