find a word in a text and take a part of a text

[Dim Dioannou]

I want to find a word in a text file and then to take a part of it and to
save it in a String.
for example I have this part of text
<rdf:RDF
xmlns:rdf='http://www.w3.org/1999/02/22-rdf-syntax-ns#'

and when I find the word ''xmlns:'' I want to take the word after : till =
(rdf in this case) and to put it in a string.

Any idea how to do it?

[Hunter McMillen]

is the text always going to have that same pattern of "xmlns:"? If you you could use regular expressions to find this pretty easily.

Hunter

[Jesper de Jong]

Welcome to the Ranch!

Your question sounds a lot like this one that was asked yesterday. I posted an answer there that might be useful to you.

[Harlin Seritt]

You can do something like this in a tight:

String text = "<rdf:RDF
xmlns:rdf='http://www.w3.org/1999/02/22-rdf-syntax-ns#'";

String del1 = "xmlns:";

String newString = text.split(del1)[1].split("=")[0];

System.out.println(newString);

But a regular expression would be the way to go.

[kumarjit banerjee]

Dim Dioannou wrote:I want to find a word in a text file and then to take a part of it and to
save it in a String.
for example I have this part of text
<rdf:RDF
xmlns:rdf='http://www.w3.org/1999/02/22-rdf-syntax-ns#'

and when I find the word ''xmlns:'' I want to take the word after : till =
(rdf in this case) and to put it in a string.

Any idea how to do it?

You may try this.

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class CountString {

	public static void main(String[] args){

		ArrayList<String> as = new ArrayList<String>();
		
		try {
			BufferedReader br = new BufferedReader(new FileReader("test.txt"));
		try {
			String s = br.readLine();
			while(s!=null){
				getValue(s,"xmlns:.*?=",as);
				s=br.readLine();
				}
			System.out.println(as);
			
		} catch (IOException e) {
			e.printStackTrace();
		}
   	} catch (FileNotFoundException e) {
			e.printStackTrace();
		}
	}
	
	public static ArrayList<String> getValue(String exp,String subexp,ArrayList<String> as){
		
		Pattern p = Pattern.compile(subexp);
		Matcher m = p.matcher(exp);
		while(m.find()){
			as.add(String.copyValueOf(m.group().toCharArray(), 6, m.group().length()-7));
		}
		return as;
	}
}

[Dim Dioannou]

@kumarjit banerjee thank you
this is what i need

but can you explain the code in line 38, please?

[kumarjit banerjee]

Dim Dioannou wrote:@kumarjit banerjee thank you
this is what i need

but can you explain the code in line 38, please?

Hi


as.add(String.copyValueOf(m.group().toCharArray(), 6, m.group().length()-7));


This line copies the matched string (m.group returns the total matched string) from the characters of at position 6 to total length-7, this because

xmlns: length=6
= length=1

So the total length =7

Hence the code.

[Ulf Dittmer]

All the approaches suggested so far are horribly brittle. It's perfectly possible for the XML to change in various valid ways that would break your code. Regexps simply are not capable of dealing with that. If you're handling XML, you need to use XML/DOM APIs.