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Andri First

Joined: Jul 07, 2011
Posts: 2
Dear All,

i am able to execute the file at Http://localhost:8080/Test/indexA.jsp.
The location : C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\Test\IndexA

please help how to execute of the file location = D:\JSProject\Work\indexB.jsp

As the content of IndexA = IndexB.

thank you and respectfully,
Vijitha Kumara

Joined: Mar 24, 2008
Posts: 3902

Welcome to the Ranch!

First case you are actually executing a jsp which is installed under a web application called "Test" in Tomcat. The latter is just a file residing in the file system (I assume without the control of a server). So you cannot access that the same way as the other.

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Andri First

Joined: Jul 07, 2011
Posts: 2
Dear Vijitha,

can we set the order for tomcat to refer to our folder preference....instead of using the default folder /.../"webapps"

thank you
I agree. Here's the link:
subject: Localhost
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