Directory / File not found

[Paulo Carvalho]

Hello

I deployed a WAR file into Tomcat. This WAR file has a JAR file inside. Inside this JAR file, there is a directory structure: a directory called "mods" with a "fr" subdirectory.

So, the JAR file have something like this:

...
META-INF
mods
fr
...


The JAR file has a java class which tries to access the mods/fr directory:

                ...
                final File f = new File("mods/fr");
		if(!f.exists() && !f.isDirectory()) {
			return new InfoResult(InfoResult.NOT_OK, 
				null, dir + " directory does not exist!");
		}
                ...

Unfortunally, the directory is not found.

I have put the following lines to verify this:

      System.out.println(ff.getAbsolutePath());  

=> it prints "C:\Programs\apache-tomcat-6.0.24\bin\mods\fr"

System.out.println(ff.isDirectory());
System.out.println(ff.exists());

=> it prints "false" and "false".


What am I missing? how can I do for mods/fr directory to be found my the class of the JAR which is into the WAR file?

Thanks
Best regards

[Ogeh Ikem]

Hello Paulo. Are you trying to access a resource in that directory? In that case,

use this

URL url = getClass().getResource("/mod/fr/ResourceName.extension");

or this

InputStream inputstream = getClass().getResourceAsStream("/mod/fr/ResourceName.extension");

[Bear Bibeault]

A jar file is not a file system. You cannot use file I/O. As pointed out, you must obtain it as a resource.

[Paulo Carvalho]

Hello

Thanks for the answers.

In fact, what I want to do is to access the "mods/fr" directory which is in the JAR file and list all the files that ends with the "txt" extension.

So, resuming, I don't have the name of the ressource files, I just have the name of the directory where they are...

How can I list all the "txt" files present in the directory?

Thank you

Regards

[Ogeh Ikem]

Use this code to print the name of every file in a jar file.

You can implement a simple filter to print only the names of files in the "mods/fr" directory that end with the "txt" extension.

class PrintFileNames {
	FileInputStream fis; 
	JarInputStream jis; 
	void readJarEntries() {
        try {
        	fis = new FileInputStream("C://pathtojarfile//JarFile.jar");
        	jis = new JarInputStream(fis, false);
            JarEntry entry;
            while ((entry = jis.getNextJarEntry()) != null) {
                System.out.println(entry.getName());
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
        finally {
        	try {
                jis.close();
                fis.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
	}
	public static void main(String[] args) {
		new PrintFileNames().readJarEntries();
	}
}

[Paulo Carvalho]

Thanks for the clue.
I will try it.

Best regards