Meaningless Drivel is fun!*
The moose likes Beginning Java and the fly likes help with arrays program in java Big Moose Saloon
  Search | Java FAQ | Recent Topics | Flagged Topics | Hot Topics | Zero Replies
Register / Login


Win a copy of Android Security Essentials Live Lessons this week in the Android forum!
JavaRanch » Java Forums » Java » Beginning Java
Bookmark "help with arrays program in java" Watch "help with arrays program in java" New topic
Author

help with arrays program in java

Jr Winston
Greenhorn

Joined: Jul 22, 2011
Posts: 5
Hi all. I have to write a java program that allows a user to enter an octal digit and output the binary equivalent for as many numbers as the person wishes using a direct access method.

The error is that even though it compiles, it loops the binary equivalent. The code goes as follows:


import java.util.Scanner; // initialize scanner class for input
public class Arrays
{
public static void main(String[] args)
{
int num = 0;
String OctalNum;
// declare array to hold 7 octal numbers and convert to binary numbers
int i;
int j;
int n;

char c; //to hold each number of input octal

char repeat; //to hold yes or no

//for numbers 1 to 7, make a binary equivalent

String binaryArray[]={"000", "001", "010", "011", "100", "101", "110", "111"};


do
{


Scanner input = new Scanner(System.in);
System.out.println("Octal to Binary Conversion");

System.out.println("Enter the Octal Number: ");
OctalNum = input.nextLine();


// make a loop to read as many numbers as the input octal has
for (i=0; i < OctalNum.length(); i++)
{
//read string by character then convert to an integer

c = OctalNum.charAt(0);

for (j=1; j < c; j++)
{
//convert character to integer (ex: "1" to 1)
n = Character.getNumericValue(c);
if(n <8)
{
binaryArray[0] = "000";
binaryArray[1] = "001";
binaryArray[2] = "010";
binaryArray[3] = "011";
binaryArray[4] = "100";
binaryArray[5] = "101";
binaryArray[7] = "111";

System.out.println(OctalNum+ " converted to binary is "+ binaryArray[n]);

// System.out.println();

}//end if
else if(n>7)
System.out.println( "Not a valid octal number!");

}

}

// prompt for input more OctalNum
System.out.print("Do you want to enter another Octal number? ");

System.out.println("Y for yes or N for No: ");
System.out.println();

String str= input.next(); //Read next char
repeat= str.charAt(0); //Get the first char

}
while(repeat=='Y' || repeat=='y');

}
}
James E Baker
Greenhorn

Joined: Jul 28, 2011
Posts: 23
Hi Jr....

First... to save you some grief when posting, make sure to use "code" button when posting code on the forum to make it easier to read and reply to.

I'm not 100% sure I know exactly how you want your output to look, but I have four suggestions for you to try.

1. At the beginning, you have the line "int num = 0;" for no apparent reason. It is never used in your code.
2. You have a line "c = OctalNum.charAt(0); " which I think you should change to "c = OctalNum.charAt(i); "
3. What is the "for (j=1; j < c; j++) " about? I would completely delete that from your code. It doesn't seem to serve a purpose and "c" is a char value not an int.
4. Change your output to "System.out.println(n+ " converted to binary is "+ binaryArray[n]); "

Below shows the changes I made....


My output is....

Octal to Binary Conversion
Enter the Octal Number:
0123
0 converted to binary is 000
1 converted to binary is 001
2 converted to binary is 010
3 converted to binary is 011
Do you want to enter another Octal number? Y for yes or N for No:
Jr Winston
Greenhorn

Joined: Jul 22, 2011
Posts: 5
thanks! i understand it now.
 
I agree. Here's the link: http://aspose.com/file-tools
 
subject: help with arrays program in java
 
Similar Threads
August Newsletter Puzzle
Reading a stream from a socket
Hexadecimal Question
How to think in Octal?
doubt on java fundamental mock exam