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storing a set of integers in an array
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Khair Bahir
Greenhorn
Joined: Aug 01, 2011
Posts: 14
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Hello,
I'm trying to generate 50 random integers between 0 and 10 using a 'for' construct and the 'Math.random()' method. I know how to do this, but I don't know how to store all these integers in an array (one dimension). I really only know how to store integers by manually inputting them into the array. I haven't made much progress and could use some help.
This was my attempt (it doesn't work):
Thanks.
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Abhinav Kumar Mishra
Greenhorn
Joined: Jul 25, 2011
Posts: 6
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kae cee wrote:Hello,
I'm trying to generate 50 random integers between 0 and 10 using a 'for' construct and the 'Math.random()' method. I know how to do this, but I don't know how to store all these integers in an array (one dimension). I really only know how to store integers by manually inputting them into the array. I haven't made much progress and could use some help.
This was my attempt (it doesn't work):
Thanks.
hi
In the above code double value returned by random() function is converted into int before multiplication with 11.So we have to put the statement as
array[j]=(int)(Math.random()*11);
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Matthew Brown
Bartender
Joined: Apr 06, 2010
Posts: 3865
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When you say "it doesn't work"...what does happen?
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fred rosenberger
lowercase baba
Bartender
Joined: Oct 02, 2003
Posts: 10043
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do you know your operator precedence? Specifically, which is higher - a cast, or multiplication?
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Never ascribe to malice that which can be adequately explained by stupidity.
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Khair Bahir
Greenhorn
Joined: Aug 01, 2011
Posts: 14
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Yeah, I know now that casts take higher precedence than multiplication operators, which is why the program just displayed a bunch of zeroes when I omitted a set of parentheses. Thanks for your guys' help.
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Pradeep allada
Greenhorn
Joined: Jul 28, 2011
Posts: 17
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have you tried instructions given by Mr. Abhinav Kumar Mishra,
check it once
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subject: storing a set of integers in an array
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